**Rates**

can also be called:

rates of changederivatives

# How do I calculate rates?

Calculating changes through time in the geosciences

Calculating changes through time in the geosciences

## Introduction to rates

Change and time are two of the main themes in the geosciences. For example, geomorphologists study changes in landscape such as beach erosion, geochemists study chemical changes in rocks as they are weathered, climatologists study long-term changes in global and regional weather and climate. Because geologists are interested in how rapidly changes can occur, we also look at the time over which those changes took place. Combined, this creates a rate, the rapidity in which change occurs.

## What is a rate?

**Any change with respect to time is called a rate.**

This is represented mathematically by

Where

**R**is the rate,

**ΔX**is the change in whatever you are looking at (it could be temperature, pressure, distance, or anything else) and

**Δt**is the change in time. In mathematics and many science fields,

**Δ**means "change".

**ΔX**and

**Δt**:

**ΔX = X**and

_{2}-X_{1}**Δt = t**

_{2}-t_{1}However many students can figure it out using without these additional formulas.

There are many rates in the geosciences - plate tectonic velocities (distance over time), crystal growth rates (change in crystal size over time), river and groundwater discharge (volume change over time), decay rates (change in number of parent isotopes over time), or any variable that is divided by time.

*"rate equals distance over time"*(or the more accurate version "

*velocity equals distance over time*"). This can be written in equation form as:

where

**d**= distance,

**t**= time,

**R**= rate and

**V**= velocity. This is just a specific example of a rate because distance (

**d**) is the change in position,

**ΔX**.

## How do I calculate a rate?

**In 1892, the terminus of Nisqually Glacier, on the southern side of Mt. Rainier in Washington, was located 40 meters above the current position of the Nisqually river bridge. In 1951, the terminus was located 790 m above the bridge. Calculate Nisqually Glacier's rate of retreat from the bridge (in m per year) between 1892 and 1951.**

The steps to answer this question are:

- Determine which changing variable is ΔX and which is Δt.
When calculating a rate, one variable is always time (Δt), and it is most often easiest to pick this out. In this problem it is the time that has elapsed which is Δt. The other property that is changing is the
**position**(the location of the terminus), so this is ΔX. - Calculate ΔX and Δt to determine the change in the variable(s).
In the glacier problem, there are two variables that change - position (ΔX) and time (Δt).

Let's begin by calculating the change in position (ΔX); we need to know the difference between the 1892 and the 1951 positions, so we should subtract:

**790 m - 40 m = 750 m = ΔX**

Next we need to calculate the amount of time that elapsed. In other words, how many years are there between 1892 and 1951?

**1951 - 1892 = 59 years**=**Δt** - Calculate the rate using ΔX and Δt.
- Check to see what the units on your final number should be.
In this case, we are asked to calculate a rate in meters per year. Do we have units of meters and years? Yes!If your units are not the same as what is needed at the end of the problem (for example, if we had km and years), you can visit the unit conversions module to learn how to convert units.
**Just don't forget to come back and finish this page**(just hit the "back" button on your browser)**!!** - Evaluate your answer. Does that number seem reasonable?
This is one of the most important steps; if the number you had gotten was 12,700 meters per year then the glacier would have retreated more than the height of the mountain in a single year - not likely. If you had gotten .0078 meters per year, that is less than a centimeter (a quarter of an inch or so) and that would not be measurable. As it turns out, in North America glaciers typically have been retreating at rates of 3-25 m per year. Since our rate falls somewhere in the middle, it's probably reasonable.

## Determining rates from a graph

Geoscientists often present data in a graph. Any graph that has time as the horizontal axis can be used to determine a rate. In these cases, the rate is the slope of the line on the graph (many of you will know this as "rise over run") or the change in the vertical axis variable divided by the change in time (on the horizontal axis).

For practice, let's take a look at the plot at the right (you can click on it to make it bigger). In 1950, population was approximately 2.5 billion people. In 2000, world population had grown to a little over 6 billion people. So, let's calculate the rate of population growth from 1950 to 2000.

Slope is the rise over the run; this is the same as our equation for a rate since the change in time on the horizontal axis and is thus the "run."One slightly confusing thing is that our change in population, ΔX, is on the vertical axis (sometimes called the y-axis,) while Δt is on the horizontal axis (often called the x-axis.) To avoid confusion, use the rate equation above or "slope is rise over run."

So the rate of population growth between 1950 and 2000 is0.07 billion people per year(that is 70 million people added to the planet every year on average!).

## Where are rates used in geology?

Rates are used in a range of topics in introductory geoscience courses:**plate tectonics**

**rocks (igneous, metamorphic and sedimentary)****Earth history****streams and groundwater**

**glaciers****mountain building and erosion****climate change****population growth****and almost any other chapter in your textbook.**

## Next Steps

I think I understand how to calculate rates!

**Take me to the practice problems!**

I still need more help! Continue below to get more help.

## I know the rate, this question is asking for something different!

Sometimes we have information about the rate but are asked to solve for another variable (time, distance, volume, etc.). The basic equation is still the same but you will need to rearrange it to solve for a different variable. The Math You Need, When You Need It has an entire module dedicated to rearranging equations (if you click that link, don't forget to come back and practice your newly learned steps!). The Rearranging Equations sample problems have several problems (right at the top of the page) that help you solve for distance and/or time if you know the velocity!

## Resources for rates and calculating velocity

**Reaction rates in chemistry**helps students calculate reaction rates for chemical reactions.

**Calculating rates of change and slope for a graph**describes and explains the process of finding the slope of a function, and thus the rate. This is from M. Casco Learning Center and has some nice mathematical applets.

^{by Dr. Eric M. Baer, Geology Program, Highline Community College and Dr. Jennifer M. Wenner, Geology Department, University of Wisconsin Oshkosh}